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Difference between revisions of "Talk:Function of bounded variation"

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(nice, but)
 
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: Very nice. But I wonder, why $|f(b_i)-f(a_i)|$ in the classical definition. I am used to $|f(a_{i+1})-f(a_i)|$, and [http://en.wikipedia.org/wiki/Bounded_variation#Formal_definition Wikipedia] does so. After thinking a bit I see that it is equivalent, but is there a reason to prefer this way? --[[User:Boris Tsirelson|Boris Tsirelson]] 07:44, 28 August 2012 (CEST)
 
: Very nice. But I wonder, why $|f(b_i)-f(a_i)|$ in the classical definition. I am used to $|f(a_{i+1})-f(a_i)|$, and [http://en.wikipedia.org/wiki/Bounded_variation#Formal_definition Wikipedia] does so. After thinking a bit I see that it is equivalent, but is there a reason to prefer this way? --[[User:Boris Tsirelson|Boris Tsirelson]] 07:44, 28 August 2012 (CEST)
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::No. And indeed all references I have looked at use the Wikipedia convention (I wonder now where I got the other one...). I will adjust it to the usual convention. [[User:Camillo.delellis|Camillo]] 08:39, 28 August 2012 (CEST)

Latest revision as of 06:39, 28 August 2012

I am currently rewriting this entry ex novo: for the actual status of the work see User:Camillo.delellis/sandbox.

Camillo 19:17, 11 August 2012 (CEST)

Very nice. But I wonder, why $|f(b_i)-f(a_i)|$ in the classical definition. I am used to $|f(a_{i+1})-f(a_i)|$, and Wikipedia does so. After thinking a bit I see that it is equivalent, but is there a reason to prefer this way? --Boris Tsirelson 07:44, 28 August 2012 (CEST)
No. And indeed all references I have looked at use the Wikipedia convention (I wonder now where I got the other one...). I will adjust it to the usual convention. Camillo 08:39, 28 August 2012 (CEST)
How to Cite This Entry:
Function of bounded variation. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Function_of_bounded_variation&oldid=27814