Difference between revisions of "Talk:Evolution operator"
From Encyclopedia of Mathematics
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:Yes. Looking at [http://enc-dic.com/enc_math/Jevoljucionn-operator-5540.html the corresponding article in Russian] I do not understand, wherefrom came this strange phrase. | :Yes. Looking at [http://enc-dic.com/enc_math/Jevoljucionn-operator-5540.html the corresponding article in Russian] I do not understand, wherefrom came this strange phrase. | ||
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| + | :In addition, "linear operator-function of $t$ and $s$" may seem to mean linearity in $(s,t)$ (while the operators need not be linear). But of course, the true meaning is a (nonlinear) map from $(s,t)$ to linear operators. [[User:Boris Tsirelson|Boris Tsirelson]] ([[User talk:Boris Tsirelson|talk]]) 22:22, 16 October 2017 (CEST) | ||
Latest revision as of 20:22, 16 October 2017
Parameter space
It seems that the parameters $t,s$ are usually taken to lie in some subset of the reals. The condition "If $t,s$ belong to an infinite-dimensional space" seems incorrect, and I have replaced it with the anodyne "Under some circumstances" which is consistent with the reference [a1]. Richard Pinch (talk) 20:45, 16 October 2017 (CEST)
- Yes. Looking at the corresponding article in Russian I do not understand, wherefrom came this strange phrase.
- In addition, "linear operator-function of $t$ and $s$" may seem to mean linearity in $(s,t)$ (while the operators need not be linear). But of course, the true meaning is a (nonlinear) map from $(s,t)$ to linear operators. Boris Tsirelson (talk) 22:22, 16 October 2017 (CEST)
How to Cite This Entry:
Evolution operator. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Evolution_operator&oldid=42093
Evolution operator. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Evolution_operator&oldid=42093