Difference between revisions of "Euclidean prime number theorem"
From Encyclopedia of Mathematics
(Importing text file) |
m (dots) |
||
| (2 intermediate revisions by the same user not shown) | |||
| Line 1: | Line 1: | ||
| + | {{TEX|done}} | ||
The set of prime numbers is infinite (Euclid's Elements, Book IX, Prop. 20). The [[Chebyshev theorems on prime numbers|Chebyshev theorems on prime numbers]] and the asymptotic law of the [[Distribution of prime numbers|distribution of prime numbers]] provide more precise information on the set of prime numbers in the series of natural numbers. | The set of prime numbers is infinite (Euclid's Elements, Book IX, Prop. 20). The [[Chebyshev theorems on prime numbers|Chebyshev theorems on prime numbers]] and the asymptotic law of the [[Distribution of prime numbers|distribution of prime numbers]] provide more precise information on the set of prime numbers in the series of natural numbers. | ||
| Line 4: | Line 5: | ||
====Comments==== | ====Comments==== | ||
| − | The proof of the Euclidean theorem is simple. Suppose there exist only finitely many prime numbers | + | The proof of the Euclidean theorem is simple. Suppose there exist only finitely many prime numbers $p_1,\dotsc,p_k$. Consider the number $N=p_1\dotsm p_k+1$. Since $N>1$ it must be divisible by a prime number $p$, which equals some $p_i$ due to the finiteness of the amount of prime numbers. Hence $p=p_i$ divides $N=p_1\dotsm p_i\dots p_k+1$, and thus $p_i$ divides 1. This contradiction shows that there must be infinitely many prime numbers. |
Latest revision as of 11:52, 14 February 2020
The set of prime numbers is infinite (Euclid's Elements, Book IX, Prop. 20). The Chebyshev theorems on prime numbers and the asymptotic law of the distribution of prime numbers provide more precise information on the set of prime numbers in the series of natural numbers.
Comments
The proof of the Euclidean theorem is simple. Suppose there exist only finitely many prime numbers $p_1,\dotsc,p_k$. Consider the number $N=p_1\dotsm p_k+1$. Since $N>1$ it must be divisible by a prime number $p$, which equals some $p_i$ due to the finiteness of the amount of prime numbers. Hence $p=p_i$ divides $N=p_1\dotsm p_i\dots p_k+1$, and thus $p_i$ divides 1. This contradiction shows that there must be infinitely many prime numbers.
How to Cite This Entry:
Euclidean prime number theorem. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Euclidean_prime_number_theorem&oldid=11641
Euclidean prime number theorem. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Euclidean_prime_number_theorem&oldid=11641
This article was adapted from an original article by S.M. Voronin (originator), which appeared in Encyclopedia of Mathematics - ISBN 1402006098. See original article