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An operator <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225701.png" /> such that if <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225702.png" />, <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225703.png" /> and <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225704.png" />, then <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225705.png" /> and <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225706.png" />. (Here <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225707.png" /> are Banach spaces over the same field of scalars and <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225708.png" /> is the domain of definition of <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c0225709.png" />.) The notion of a closed operator may be extended to operators defined on separable linear topological spaces, except that instead of a sequence <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257010.png" /> one must consider arbitrary directions (nets) <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257011.png" />. If <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257012.png" /> is the graph of <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257013.png" />, then <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257014.png" /> is closed if and only if <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257015.png" /> is a closed subset of the Cartesian product <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257016.png" />. This property is often adopted as the definition of a closed operator.
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The notion of a closed operator is a generalization of the notion of an operator defined and continuous on a closed subset of a Banach space. An example of a closed but not continuous operator is <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257017.png" />, defined on the set <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257018.png" /> of continuously-differentiable functions in the space <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257019.png" />. Many operators of mathematical physics are closed but not continuous.
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An operator <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257020.png" /> has a closure (i.e. is closeable) if it admits a closed extension. An operator has a closure if and only if it follows from <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257021.png" />,
+
An operator $  A :  D _ {A} \rightarrow Y $
 +
such that if  $  x _ {n} \in D _ {A} $,
 +
$  x _ {n} \rightarrow x $
 +
and  $  A x _ {n} \rightarrow y $,
 +
then  $  x \in D _ {A} $
 +
and  $  A x = y $.  
 +
(Here  $  X , Y $
 +
are Banach spaces over the same field of scalars and  $  D \subset  X $
 +
is the domain of definition of  $  A $.)  
 +
The notion of a closed operator may be extended to operators defined on separable linear topological spaces, except that instead of a sequence  $  \{ x _ {n} \} $
 +
one must consider arbitrary directions (nets)  $  \{ x _  \xi  \} $.
 +
If  $  \mathop{\rm Gr}  A $
 +
is the graph of  $  A $,
 +
then  $  A $
 +
is closed if and only if $  \mathop{\rm Gr}  A $
 +
is a closed subset of the Cartesian product  $  X \times Y $.  
 +
This property is often adopted as the definition of a closed operator.
  
<table class="eq" style="width:100%;"> <tr><td valign="top" style="width:94%;text-align:center;"><img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257022.png" /></td> </tr></table>
+
The notion of a closed operator is a generalization of the notion of an operator defined and continuous on a closed subset of a Banach space. An example of a closed but not continuous operator is  $  A = d / dt $,
 +
defined on the set  $  C _ {1} [ a , b ] $
 +
of continuously-differentiable functions in the space  $  C [ a , b ] $.  
 +
Many operators of mathematical physics are closed but not continuous.
  
that <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257023.png" />. The smallest closed extension of an operator is called its closure. A symmetric operator on a Hilbert space with dense domain of definition always admits a closure.
+
An operator  $  A $
 +
has a closure (i.e. is closeable) if it admits a closed extension. An operator has a closure if and only if it follows from  $  x _ {n} , x _ {n}  ^  \prime  \in D _ {A} $,
  
A bounded linear operator <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257024.png" /> is closed. Conversely, if <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257025.png" /> is defined on all of <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257026.png" /> and closed, then it is bounded. If <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257027.png" /> is closed and <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257028.png" /> exists, then <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257029.png" /> is also closed. Since <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257030.png" /> is closed if and only if <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257031.png" /> is closed, it follows that <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257032.png" /> is closed if the resolvent <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257033.png" /> exists and is bounded for at least one value of the parameter <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257034.png" />.
+
$$
 +
\lim\limits  x _ {n}  = \lim\limits  x _ {n}  ^  \prime  ,\  \lim\limits  A x _ {n}  = y ,\  \lim\limits  A x _ {n}  ^  \prime  = y  ^  \prime  ,
 +
$$
  
If <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257035.png" /> is dense in <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257036.png" /> and, consequently, the adjoint operator <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257037.png" />, <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257038.png" />, is uniquely defined, then <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257039.png" /> is a closed operator. If, moreover, <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257040.png" /> is dense in <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257041.png" /> and <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257042.png" /> are reflexive, then <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257043.png" /> is a closeable operator and its closure is <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257044.png" />.
+
that  $  y = y  ^  \prime  $.
 +
The smallest closed extension of an operator is called its closure. A symmetric operator on a Hilbert space with dense domain of definition always admits a closure.
 +
 
 +
A bounded linear operator  $  A : X \rightarrow Y $
 +
is closed. Conversely, if  $  A $
 +
is defined on all of  $  X $
 +
and closed, then it is bounded. If  $  A $
 +
is closed and  $  A  ^ {-} 1 $
 +
exists, then  $  A  ^ {-} 1 $
 +
is also closed. Since  $  A :  X \rightarrow X $
 +
is closed if and only if  $  A - \lambda I $
 +
is closed, it follows that  $  A $
 +
is closed if the resolvent  $  R _  \lambda  ( A ) = ( A - \lambda I )  ^ {-} 1 $
 +
exists and is bounded for at least one value of the parameter  $  \lambda \in \mathbf C $.
 +
 
 +
If  $  D _ {A} $
 +
is dense in $  X $
 +
and, consequently, the adjoint operator $  A  ^ {*} : D _ {A  ^ {*}  } \rightarrow X  ^ {*} $,  
 +
$  D _ {A  ^ {*}  } \subset  Y  ^ {*} $,  
 +
is uniquely defined, then $  A  ^ {*} $
 +
is a closed operator. If, moreover, $  D _ {A  ^ {*}  } $
 +
is dense in $  Y  ^ {*} $
 +
and $  X , Y $
 +
are reflexive, then $  A $
 +
is a closeable operator and its closure is $  A  ^ {**} $.
  
 
A closed operator can be made bounded by introducing a new norm on its domain of definition. Let
 
A closed operator can be made bounded by introducing a new norm on its domain of definition. Let
  
<table class="eq" style="width:100%;"> <tr><td valign="top" style="width:94%;text-align:center;"><img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257045.png" /></td> </tr></table>
+
$$
 +
\| x \| _ {0= \| x \| _ {X} + \| Ax \| _ {Y} .
 +
$$
  
Then <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257046.png" /> with this new norm is a Banach space and <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257047.png" />, as an operator from <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257048.png" /> to <img align="absmiddle" border="0" src="https://www.encyclopediaofmath.org/legacyimages/c/c022/c022570/c02257049.png" />, is bounded.
+
Then $  D _ {A} $
 +
with this new norm is a Banach space and $  A $,  
 +
as an operator from $  ( D _ {A} , \| \cdot \| _ {0} ) $
 +
to $  Y $,  
 +
is bounded.
  
 
====References====
 
====References====
 
<table><TR><TD valign="top">[1]</TD> <TD valign="top">  K. Yosida,  "Functional analysis" , Springer  (1980)</TD></TR><TR><TD valign="top">[2]</TD> <TD valign="top">  T. Kato,  "Perturbation theory for linear operators" , Springer  (1980)</TD></TR></table>
 
<table><TR><TD valign="top">[1]</TD> <TD valign="top">  K. Yosida,  "Functional analysis" , Springer  (1980)</TD></TR><TR><TD valign="top">[2]</TD> <TD valign="top">  T. Kato,  "Perturbation theory for linear operators" , Springer  (1980)</TD></TR></table>
 
 
  
 
====Comments====
 
====Comments====

Revision as of 17:44, 4 June 2020


An operator $ A : D _ {A} \rightarrow Y $ such that if $ x _ {n} \in D _ {A} $, $ x _ {n} \rightarrow x $ and $ A x _ {n} \rightarrow y $, then $ x \in D _ {A} $ and $ A x = y $. (Here $ X , Y $ are Banach spaces over the same field of scalars and $ D \subset X $ is the domain of definition of $ A $.) The notion of a closed operator may be extended to operators defined on separable linear topological spaces, except that instead of a sequence $ \{ x _ {n} \} $ one must consider arbitrary directions (nets) $ \{ x _ \xi \} $. If $ \mathop{\rm Gr} A $ is the graph of $ A $, then $ A $ is closed if and only if $ \mathop{\rm Gr} A $ is a closed subset of the Cartesian product $ X \times Y $. This property is often adopted as the definition of a closed operator.

The notion of a closed operator is a generalization of the notion of an operator defined and continuous on a closed subset of a Banach space. An example of a closed but not continuous operator is $ A = d / dt $, defined on the set $ C _ {1} [ a , b ] $ of continuously-differentiable functions in the space $ C [ a , b ] $. Many operators of mathematical physics are closed but not continuous.

An operator $ A $ has a closure (i.e. is closeable) if it admits a closed extension. An operator has a closure if and only if it follows from $ x _ {n} , x _ {n} ^ \prime \in D _ {A} $,

$$ \lim\limits x _ {n} = \lim\limits x _ {n} ^ \prime ,\ \lim\limits A x _ {n} = y ,\ \lim\limits A x _ {n} ^ \prime = y ^ \prime , $$

that $ y = y ^ \prime $. The smallest closed extension of an operator is called its closure. A symmetric operator on a Hilbert space with dense domain of definition always admits a closure.

A bounded linear operator $ A : X \rightarrow Y $ is closed. Conversely, if $ A $ is defined on all of $ X $ and closed, then it is bounded. If $ A $ is closed and $ A ^ {-} 1 $ exists, then $ A ^ {-} 1 $ is also closed. Since $ A : X \rightarrow X $ is closed if and only if $ A - \lambda I $ is closed, it follows that $ A $ is closed if the resolvent $ R _ \lambda ( A ) = ( A - \lambda I ) ^ {-} 1 $ exists and is bounded for at least one value of the parameter $ \lambda \in \mathbf C $.

If $ D _ {A} $ is dense in $ X $ and, consequently, the adjoint operator $ A ^ {*} : D _ {A ^ {*} } \rightarrow X ^ {*} $, $ D _ {A ^ {*} } \subset Y ^ {*} $, is uniquely defined, then $ A ^ {*} $ is a closed operator. If, moreover, $ D _ {A ^ {*} } $ is dense in $ Y ^ {*} $ and $ X , Y $ are reflexive, then $ A $ is a closeable operator and its closure is $ A ^ {**} $.

A closed operator can be made bounded by introducing a new norm on its domain of definition. Let

$$ \| x \| _ {0} = \| x \| _ {X} + \| Ax \| _ {Y} . $$

Then $ D _ {A} $ with this new norm is a Banach space and $ A $, as an operator from $ ( D _ {A} , \| \cdot \| _ {0} ) $ to $ Y $, is bounded.

References

[1] K. Yosida, "Functional analysis" , Springer (1980)
[2] T. Kato, "Perturbation theory for linear operators" , Springer (1980)

Comments

The result that a closed linear operator mapping (all of) a Banach space into a Banach space is continuous is known as the closed-graph theorem.

References

[a1] S. Goldberg, "Unbounded linear operators" , McGraw-Hill (1966)
How to Cite This Entry:
Closed operator. Encyclopedia of Mathematics. URL: http://encyclopediaofmath.org/index.php?title=Closed_operator&oldid=11562
This article was adapted from an original article by V.I. Sobolev (originator), which appeared in Encyclopedia of Mathematics - ISBN 1402006098. See original article